3x(1.06^5)x(1.06^-3)+x=2500(1.06^-2)

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Solution for 3x(1.06^5)x(1.06^-3)+x=2500(1.06^-2) equation: 



3x(1.06^5)x(1.06^-3)+x=2500(1.06^-2)

We move all terms to the left:

3x(1.06^5)x(1.06^-3)+x-(2500(1.06^-2))=0

We add all the numbers together, and all the variables

x+3x(1.06^5)x(1.06^-3)-2224.9911000356=0

We move all terms containing x to the left, all other terms to the right

x+3x(1.06^5)x(1.06^-3)=2224.9911000356

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